Well you do 32 divided by 28% and get 8.96
Answer:
6000 in³
Step-by-step explanation:
To solve this problem, we simply have to find the volume of the shipping container that will be just enough to contain the 20 soda boxes.
To do this, we find the volume of each soda box and multiply it by the total number of soda boxes held by the shipping container.
Volume of the box = L * B * H
L = length = 15 in
B = breadth = 4 in
H = height = 5 in
V = 15 * 4 * 5 = 300 in³
This is the volume of each soda box.
The volume of 20 soda boxes will then be:
V = 20 * 300 = 6000 in³
This is the volume of 20 soda boxes and hence, the minimum size the shipping container can be.
40/40
8x5=40
10x4=40
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Answer:
x=15
Step-by-step explanation:
21:2x=7:10 can be rewritten as 21/2x=7/10
21/2x=7/10, cross multiply
= 14x=210
x=15
