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lara31 [8.8K]
2 years ago
11

PLEASE HELP ME I REALLY NEED IT

Mathematics
1 answer:
ycow [4]2 years ago
7 0
It’s A
Divide 32,400 by twelve
32,400/12=2,700
2,700x4 equals the amount depreciated in 4 years which equals 10,800
Subtract 10,800 from the original value 32,400-10,800= 21,600
A is your answer
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What is a squared plus b squared equal c squared?
Ostrovityanka [42]
A^2+b^2=c^2 is known as the Pythagorean theorem. It is used to describe the relationship of the lengths of the sides of a right triangle.
8 0
2 years ago
In 1 hr, a plane can travel 440 mi into the wind and 480 mi with the wind. Find the wind speed and the rate of the plane in stil
nexus9112 [7]

Answer:

the plane would fall and crash at 150mph

Step-by-step explanation:

8 0
3 years ago
Which is the standard form of the equation of the parabola that has a vertex of (3, 1) and a directric of x = -2?
vagabundo [1.1K]
Check the picture below.  So,the parabola looks like so, notice the distance "p". since the parabola is opening to the right, then "p" is positive, thus is 5.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\

\bf -------------------------------\\\\
\begin{cases}
h=3\\
k=1\\
p=5
\end{cases}\implies (y-1)^2=4(5)(x-3)\implies (y-1)^2=20(x-3)
\\\\\\
\cfrac{1}{20}(y-1)^2=x-3\implies \boxed{\cfrac{1}{20}(y-1)^2+3=x}

8 0
3 years ago
Read 2 more answers
The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula
Semmy [17]

Answer:

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

V=\frac{4}{3} \pi r^{3}

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

V=\frac{4}{3} \pi r^{3}   ......Given

3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

5 0
3 years ago
Help please! (no links)
disa [49]
EZ is 24.5
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3 years ago
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