Answer:
Let's give names to the all sides a=6 , b=9 and c=?
Third sides of an triangle is determined by the following double inequality, in this case b>a => b-a < c < b+a => 9-6 < c < 9+6 =>
3 < c < 15 => c belongs to the interval (3,15), let's take c=4, if we check for example side b => a>c => a-c < b < a=c => 6-4 < 9 < 6+4 =>
2 < 9 < 10 , inequality is true.
The answer is 12
6×12= 24
6×12=72
A
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = ( multiply both sides by x³ )
x³y = 19 ( divide both sides by y )
x³ = ( take the cube root of both sides )
x =
Change y back into terms of x, then
(x) = = → A
x = y =
= 90