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allsm [11]
3 years ago
7

Find the five-number summary for the given data. Min Q1 Q2 Q3 Max

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer with Step-by-step explanation:

16 19 21 26 27 29 34 35 35 39 40 41 42 50 50 52 57 60 75 76 78 81 84

the data is already arranged in ascending order

Min=16

Max=84

The quartiles for the odd set of data is given by

Qi=\dfrac{i(n+1)}{4}\ th\ term

where n is the number of elements

Here, n=23

Q1=\dfrac{(23+1)}{4}\ th\ term

Q1=6 th term

Q1=29

Q2=12 th term

Q2=41

Q3=18 th term

Q3=60

Hence, five-number summary for the given data is:

Min  Q1   Q2   Q3   Max

16     29   41     60    84

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3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
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Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
2 years ago
Read 2 more answers
Please Help<br> Question; What is the value of x?
Maksim231197 [3]

Answer:

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Step-by-step explanation:

x+5/30 = 16/20

20x+100=480

20x=380

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