Answer:
AKPOS/ACGF = 28√3 -48 ≈ 0.497423
Step-by-step explanation:
Let's assume the square is a unit square. Then the height of the triangle is ...
1 +(√3)/2 = h
and half the base of the triangle is ...
h/√3 = (√3)/3 +1/2 = b/2
The area of the triangle is the product of these:
A = (1/2)bh
= (2 +√3)/2 × (3 +2√3)/6
= (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12
So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...
(square area)/(triangle area) = 12/(12+7√3)
(square area)/(triangle area) = 28√3 -48
Answer: I'm pretty sure it's 200x - 120x = 1,200
Step-by-step explanation:
The answer to this question would be 5 by 9.
Answer:
Let the distance between woman and pole be "x".
From diagram,
In ΔOAB,
tan 18 = 
tan 18 = 
∴ x = 
................ (1)
In ΔOBC
tan 14 =
tan 14 = 
y = x × tan 14 ..............(2)
equating (2) in (1), we get;
x = 
x = 
∵ tan 18 + tan 14 = 0.574
<em>∴ x = 113.2 ft</em>
<em>i.e. The her distance from the pole is 113.2 ft.</em>
Answer:
X is an acute angle, which means it is less than 90*, so it is probably 45*
Step-by-step explanation:
I was confused at first but then, I’m just like, I can solve this!
