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nirvana33 [79]
3 years ago
8

I need help on number 1

Mathematics
1 answer:
prisoha [69]3 years ago
7 0
I hop this is right number 3
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Evaluate 18 -8(14 + 4) + 42.
Alina [70]

Answer:

-84

Step-by-step explanation:

4 0
3 years ago
A bag contains 5 blue marbles, 2 green marbles, and 3 yellow marbles. What is the probability of choosing one green marble and t
Vesna [10]

Answer:

Step-by-step explanation:

Total number of marbles = 5 + 2 + 3 = 10

Probability of choosing 1 green marble = 2/10

Probability of choosing 1 yellow marble = 3/10

Notice (and this is important) that the denominator didn't change. Why?

Because you replaced the first marble into the bag. That word replacement is critical in a problem of this nature. There is the term non replacement which means that the second draw would have a denominator of 9.

So what is the probability of P(green then yellow)?

P(green then yellow) = 3/10 * 2/10 = 6/100

Answer: P(green then yellow) = 3/50 because 6 / 100 reduces.

4 0
2 years ago
PLEASE PLEASE HELP ME!!!
leonid [27]
I tried to show all work.

8 0
2 years ago
Read 2 more answers
Help plz MATH question for ASM
jok3333 [9.3K]

9514 1404 393

Answer:

  6. step 2; terms are improperly combined; it should be -61n-8=-8

  7. no; point (2, 5) is not part of the solution in the left graph

Step-by-step explanation:

6. Step 2 should be ...

  -61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n

__

7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.

The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.

The point (2, 5) is not a solution to both inequalities.

4 0
3 years ago
Read 2 more answers
a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig
Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when h=0, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

5 0
2 years ago
Read 2 more answers
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