GCF and LCM of Integers and Monomials
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Answer:
The quadratic equation used to determine the thickness of frame is
Step-by-step explanation:
Refer to the attachment for the diagram.
Consider EFGH as the the frame and ABCD as the mirror which is to be hanged.
Let me the "x" be the thickness of the frame as shown in diagram.
Given that, BC = 3 ft and DC = 2 ft which is the dimensions of the mirror.
Now to calculate the length and width of the frame consider following calculation,
Width of frame HG = x + DC + x
Width of frame HG = x + 2 + x
Width of frame HG = 2 + 2x
2x is the addition of the thickness which is present on both side of mirror
Length of frame FG = x + BC + x
Length of frame FG = x + 3 + x
Length of frame FG = 3 + 2x
Since it is an rectangular frame, so using the formula for area of rectangle
Given that area of frame is
Substituting the value,
Therefore, the quadratic equation used to determine the thickness of frame is
