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Dahasolnce [82]
3 years ago
10

Expand : (3x+5y)²please answer​

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

FOIL:  9x^2 +30xy + 25y^2

(3x + 5y)(3x+5y)

F: 3x*3x

O: 3x*5y

I: 5y*3x

L: 5y*5y

9x^2 +30xy + 25y^2

Step-by-step explanation:

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Answer: what type of math is this

Step-by-step explanation:

3 0
3 years ago
Find the magnitude of the vector from the origin to (-7, -5) and write the vector as the sum of unit vectors.
Agata [3.3K]
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7 0
2 years ago
Write the number with the same value as 28 tens
Sonbull [250]
280 is the answer
______________________________________
                                                                                        
3 0
3 years ago
A one-tailed test is a a. hypothesis test in which rejection region is in one tail of the sampling distribution b. hypothesis te
garri49 [273]

Answer:

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

Step-by-step explanation:

One Tailed Test:

  • A one tailed test is a test that have hypothesis of the form

H_0: \bar{x} = \mu\\H_A: \bar{x} < \mu\text{ or } \bar{x} > \mu

  • A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
  • Rejection region is the area for which the null hypothesis is rejected.
  • If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.
  • If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.

Thus, for one tailed test,

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

6 0
2 years ago
Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an
Natasha_Volkova [10]

Answer:

The volume of the solid is 243\sqrt{2} \ \pi

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0  ≤ ρ²   ≤   81

0  ≤ ρ   ≤  9

The intersection that takes place in the sphere and the cone is:

x^2 +y^2 ( \sqrt{x^2 +y^2 })^2  = 81

2(x^2 + y^2) =81

x^2 +y^2 = \dfrac{81}{2}

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

z = \sqrt{x^2+y^2}

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; \dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}

Thus, volume: V  = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4}  \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho   ^2 \ sin \phi \ d\rho \   d \theta \  d \phi

V  = \int \limits^{\pi/2}_{\pi/4} \ sin \phi  \ d \phi  \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho   ^2 d\rho

V = \bigg [-cos \phi  \bigg]^{\pi/2}_{\pi/4}  \bigg [\theta  \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3}  \bigg ]^{9}_{0}

V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]

V = 243\sqrt{2} \ \pi

4 0
3 years ago
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