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Sphinxa [80]
4 years ago
12

WILL AWARD BRAINLIEST AND WORTH 25 POINTS

Mathematics
2 answers:
Nutka1998 [239]4 years ago
7 0

Answer:

  D=\left[\begin{array}{cc}0&0\\1&1\end{array}\right]

Step-by-step explanation:

The matrix equation is already set up as ...

  PD = Q

The normal method of solution is to multiply the equation by P^-1, but that matrix does not exist. Here, we'll solve by considering what the equation means, element by element.

Suppose matrix D looks like ...

  D=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

We require the product PD = Q, so that means ...

  0·a +0·c = 0

  0·b +0·d = 0

  1·a + 0·c = 0

  1·b +0·d = 0

We can see from these equations that a=0 and b=0 are required. The values of c and d can be anything you like.

A suitable matrix for D could be ...

  D=\left[\begin{array}{cc}0&0\\1&1\end{array}\right]

-Dominant- [34]4 years ago
6 0

Answer:

Below.

Step-by-step explanation:

P = (0 0)   and  Q =  (0 0)

     (1  0)                    (0 0)

  P      *     D       =                                                   Q

(0 0)  *    (0 0)   =   (0*0 + 0*1    0*0 + 0*1)  =       (0 0)

(1 0 )        (1 1)         (1*0 + 0*1    1 *0 + 0*1 )            (0 0)

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