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Paladinen [302]
3 years ago
15

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Mathematics
1 answer:
zimovet [89]3 years ago
5 0

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately  = 28-17 = 11

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3 years ago
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first, find the LCD of 3/7 and 1/3 and then combine 3/7 and -1/3).
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If that's the case, then please retype your whole question.

You could express "the quotient of 2/3 and 1/6" as follows:
   
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Is that what you meant?

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4 0
3 years ago
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Answer:

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4 0
3 years ago
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