Answer:
x = -11/9
Step-by-step explanation:
7(x+3)=-2(x-5)
Distribute
7x+21 = -2x+10
Add 2x to each side
7x+21 +2x = -2x+10+2x
9x +21 = 10
Subtract 21 from each side
9x +21-21 = 10-21
9x = -11
Divide each side by 9
9x/9 = -11/9
x = -11/9
Answer:
<em>Part A </em>C = (10,5)<em> Part B </em>C. D'(0,10)
Step-by-step explanation:
<em>Part A</em>
Since c is at the point (2,1) in relation to the origin, we can multiply those distances by our scale factor of 5
(2,1) * 5 = (10,5)
The new point C is going to be (10,5)
<em>Part B</em>
If you dilate with a factor of 5 -- relative to the origin -- you have to multiply the distance from <em>the origin</em> by 5.
In this case, point D is already on the y axis, so it's x value wouldn't be affected. Point D is currently 2 units away from (0,0), so we can multiply 2*5 to get 10 -- our ending point is (0,10)
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Answer:
both these equations are the examples of associative property.
#1 is the example of associative property with respect to multiplication.
#2 is the example of associative property with respect to addition.
Answer: $2421.95
Step-by-step explanation:
A = p(1 + r/n) ^nt
A= 2000(1+0.024/4)^4x8
A= 2421.95
