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Luden [163]
3 years ago
8

Koshi creates a password as follows: number, special character, letter, letter, number If there are 12 special characters and Ko

shi does not repeat a letter or number, how many possibilities are there for his password? a. 702,000 b. 730,080 c. 780,000 d. 811,200
Mathematics
2 answers:
bearhunter [10]3 years ago
8 0

Answer:

a.702,000

Step-by-step explanation:

Delvig [45]3 years ago
4 0
Number of possibility for 1st character = 10
Number of possibilities for 2nd character = 12
Number of possibilities for 3rd character = 26
Number of possibilities for 4th character = 25
Number of possibilities for 5th character = 9

Therefore, number of possibilities for his password = 10 x 12 x 26 x 25 x 9 = 702,000
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