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3 years ago

So um what’s the answer to this. -7(2+k)=7

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

6 0

Answer:

k = -3

Step-by-step explanation:

$-7(2+k)=7\\\\-14-7k=7\\\\-14+14-7k=7+14\\\\-7k=21\\\\\frac{-7k=21}{7}\\\\\boxed{k=-3}$

Hope this helps.

lilavasa [31]3 years ago

5 0

Answer:

k = -3

Step-by-step explanation:

-7(2 + k) = 7

Divide both sides by (-7)

2 + k = 7/-7

2 + k = -1

Subtract 2 form both sides

k = -1 - 2

k = -3

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2 years ago

The sum of 3 times the value of x and 2 is equal to four less than five times the value of x. Which equation can be used to find

bonufazy [111]

The question has omitted options but i will solve, so you will just check my answer from the options you have.

Answer: The equation to find the value of x = 3x+ 2= 5x-4

The value of x= 3

Step-by-step explanation:

Step 1

The sum of 3 times the value of x and 2 is equal to four less than five times the value of x can be expressed as

3x+ 2= 5x-4

Step 2

Solving this equation to find the value of x , we have that

3x+ 2= 5x-4

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3 years ago

Y +

Usimov [2.4K]

Question:

What is the common denominator of $y+\frac{y-3}{3}$ in the complex fraction $\frac{y+\frac{y-3}{3}}{\frac{5}{y}+\frac{2}{3 y}}$

A) $3 y(y-3)$

B) $y(y-3)$

C) $3y$

D) $3$

Answer:

Option D : 3 is the common denominator

Explanation:

It is given that the complex fraction $\frac{y+\frac{y-3}{3}}{\frac{5}{y}+\frac{2}{3 y}}$

We need to determine the common denominator of $y+\frac{y-3}{3}$ from the complex fraction.

Let us consider the fraction $y+\frac{y-3}{3}$

To find the common denominator, let us take LCM.

Thus, rewriting the above fraction as,

$\frac{y}{1} +\frac{y-3}{3}$$

The LCM can be determined by multiplying the denominators.

Thus, we get,

$1\times3=3$

Thus, the common denominator is 3.

Hence, Option D is the correct answer.

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3 years ago

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Answer:

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Step-by-step explanation:

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Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

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The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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