I'm not sure what you mean by difference, so I am guessing you meant to write "distance". If this is not the case, then feel free to report me. Anyway, to find the distance between two points you would use the distance formula.

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

Let's substitute our point coordinates into the formula. We'll substitute -1 and 6 for x_2 and x_1, and 14 and 16 for y_2 and y_1. After substituting, your formula will now look like: $d=\sqrt{(-1-6)^2+(14-16)^2}$ .

$d=\sqrt{(-1-6)^2+(14-16)^2}$

Subtract the coordinates.

$d=\sqrt{(-7)^2+(-2)^2}$

Square the subtracted coordinates.

$d=\sqrt{49+4}$

Add 49 and 4.

$d=\sqrt{53}$

Square root 53 and round the answer to the nearest tenth.

7.28 becomes 7.3.

7.3 units is the distance between points M and Z.

5 0

3 years ago

Find the Area of the figure below, composed of a rectangle with two semicircles removed. Round to the nearest tenths place.

Allisa [31]

Answer:

21.8

Step-by-step explanation:

hii so basically first we find the area of the 9 by 8 and subtract the area of the semicircles.

area of circles are πr^2, so in this situation

π4^2 which is 16π.

with this, the semicircle which is half a circle would give us

16π/2 which is 8π.

but then, we have two semicircles removed so we would have as an answer:

(9*8)-8π+8π

72-16π

then you would have to round so

16π is around 50.2

so 72-50.2 is 21.8

i hope this helped you <33

6 0

3 years ago