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3 years ago

What point is a solution to y> 2x -1 A.(0,2) B.(4,2) C.(0,-10) D.(4,1)

1 answer:

4 0

Well, we need to consider the x and y coordinates of the giben points, and check wether the y coordinate is greater than twice the x coordinate minus 1 (i.e. 2x-1):

For the first point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is 2, and 2>-1. So, this point is a solution.
For the second point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 2, and 2<7. So, this point is not a solution.
For the third point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is -10, and -10<-1. So, this point is not a solution.
For the fourth point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 1, and 1<7. So, this point is not a solution.

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Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim.

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Answer:

The claim made by the motor company was true. The old sedan, the Libra, would average less than 19 miles per gallon in the city.

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In this case we need to test the claim made by the Carter Motor Company, that their old sedan, the Libra, would average less than 19 miles per gallon in the city.

The hypothesis to test the claim is as follows:

H₀: The old sedan, the Libra, would average not less than 19 miles per gallon in the city, i.e. μ ≥ 19.

Hₐ: The old sedan, the Libra, would average less than 19 miles per gallon in the city, i.e. μ < 19.

It is provided that the conclusion is to reject the null hypothesis.

This implies that, it was concluded that the old sedan, the Libra, would average less than 19 miles per gallon in the city.

Hence, the claim made by the motor company was true.

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3 years ago

5. Write an equivalent ratio to 18:1?

Molodets [167]

Answer:

36:2

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For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =

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Given that For a certain model of car the distance $d$ required to stop the vehicle if it is traveling at $v$ mi/h is given by the formula $d=v+\frac{v^2}{20}, where [tex]d$ is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

$v+ \frac{v^2}{20} \leq75 \\ \\ 20v+v^2\leq1,500 \\ \\ v^2+20v+100\leq1,500+100 \\ \\ (v+10)^2\leq1,600 \\ \\ |v+10|\leq\sqrt{1,600} \\ \\ -40\leq v+10\leq40 \\ \\ -40-10\leqv\leq v\leq40-10 \\ \\ -50\leq v\leq30$

Therefore, the range of speed she can travel is $v\leq30\ mi/hr$

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3 years ago