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Elis [28]
3 years ago
12

Divide 59ml into two parts so that one part is 7ml less than five times the other parts​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:  The two parts are 48 ml and 11 ml.

Step-by-step explanation:

Let x= The quantity in the other part ( in ml).

Then, the quantity in the first part = 5x-7

Since , Whole part = Sum of both parts

According to the question , we have

59=5x-7+x\\\\

Add 7 on both sides , we get

66=6x

Divide both sides by 6 , we get

11=x

i.e. Value of  x= 11

Therefore , the quantity in the first part = 5(11)-7=48 ml

The quantity in the other part = 11 ml.

Hence, the two parts are 48 ml and 11 ml.

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A lorry driver charges $1800 to carry 60 tonnes of weight. How much will he charge for carrying 80 tonnes at the same rate
V125BC [204]

Answer:

$2400

Step-by-step explanation:

60 tonnes = $1800

80 tonnes = $?

= 1800 × 80/60

= $2400

4 0
3 years ago
Read 2 more answers
1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n
Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 70% of fatalities involve an intoxicated driver, hence p = 0.7.
  • A sample of 15 fatalities is taken, hence n = 15.

The probability is:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

Hence

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061

P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186

P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700

P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916

P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305

P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047

Then:

P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0
3 years ago
Find 5 consecutive integers whose sum is 244
storchak [24]

So the first integer is 61.

Then the others must be 62, 63, and 64. To check, you can add them all together. 61+62+63+64=250.

4 0
3 years ago
Find all polar coordinates of point p where p = (6, -pi/5)
Lelu [443]
Given a point in coordinates form (r,\theta), one can compute the cartesian form like this:
(r\cos\theta,r\sin\theta )
We have:
r=6,\theta=-\dfrac{\pi}{5}
We get the cartesian form then:
\left(6\cos-\dfrac{\pi}{5},6\sin-\dfrac{\pi}{5}\right)
4 0
3 years ago
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