the length of a rectangle is 5 less than twice its width. if the perimeter is 26 meters, find the dimensions of the rectangle

Mathematics

1 answer:

Feliz [49]3 years ago

7 0

The length of a rectangle is 5 less than twice its width

l = 2w - 5

perimeter is 26 meters

l + w + l + w = 26

2l + 2w = 26

2w = 26 - 2l

l = 2w - 5

l = 26 - 2l - 5

3l = 21

l = 7

w = 13 - l = 13 - 7 = 6

Answer: length 7 meters, width 6 meters

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What’s e simplified form of 2x+3-x+5

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Darnelle drew this figure and the accompanying equations.

kondor19780726 [428]

Answer:

Option D. w + x = z

Step-by-step explanation:

see the attached figure to better understand the problem

we have

$w+x+y=180$ ----> equation A

$y+z=180$ ----> equation B

equate equation A and equation B

$w+x+y=y+z$

Subtract y both sides

$w+x=z$

This equation satisfy the <em><u>Triangle Exterior Angle Theorem</u></em> (An exterior angle of a triangle is equal to the sum of the opposite interior angles)