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Crazy boy [7]
3 years ago
10

2 1/9÷2/3 help plsxxxxxxxxxxxxxxxz

Mathematics
2 answers:
vova2212 [387]3 years ago
5 0
The answer to your question is 3.666
Sauron [17]3 years ago
4 0

Answer:

19/6

Step-by-step explanation:

multiply the denominator 9 and 2, you'll get 18 then add 1. Multiply 2/3 by 3 to get 9/6. 19/9 times 9/6  = 171/54. Divide that fraction by 9 and you get 19/6.

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3 out of every 10 students ages 6 to 14 have a magazine subscription supposed are 30 students in Annabelle's class about how man
Zigmanuir [339]

Answer: 9 students

Step-by-step explanation:

10 X 3 = 30

3 X 3 = 9 students

4 0
3 years ago
LMNO is a parallelogram, with and . Which statements are true about parallelogram LMNO? Select three options.
Bas_tet [7]

Answer:

I believe the correct options are 1, 4, and 5.

5 0
3 years ago
Read 2 more answers
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x4 ln(x) (a) Find the interval on which f is incre
Ainat [17]

Answer: (a) Interval where f is increasing: (0.78,+∞);

Interval where f is decreasing: (0,0.78);

(b) Local minimum: (0.78, - 0.09)

(c) Inflection point: (0.56,-0.06)

Interval concave up: (0.56,+∞)

Interval concave down: (0,0.56)

Step-by-step explanation:

(a) To determine the interval where function f is increasing or decreasing, first derive the function:

f'(x) = \frac{d}{dx}[x^{4}ln(x)]

Using the product rule of derivative, which is: [u(x).v(x)]' = u'(x)v(x) + u(x).v'(x),

you have:

f'(x) = 4x^{3}ln(x) + x_{4}.\frac{1}{x}

f'(x) = 4x^{3}ln(x) + x^{3}

f'(x) = x^{3}[4ln(x) + 1]

Now, find the critical points: f'(x) = 0

x^{3}[4ln(x) + 1] = 0

x^{3} = 0

x = 0

and

4ln(x) + 1 = 0

ln(x) = \frac{-1}{4}

x = e^{\frac{-1}{4} }

x = 0.78

To determine the interval where f(x) is positive (increasing) or negative (decreasing), evaluate the function at each interval:

interval                 x-value                      f'(x)                       result

0<x<0.78                 0.5                 f'(0.5) = -0.22            decreasing

x>0.78                       1                         f'(1) = 1                  increasing

With the table, it can be concluded that in the interval (0,0.78) the function is decreasing while in the interval (0.78, +∞), f is increasing.

Note: As it is a natural logarithm function, there are no negative x-values.

(b) A extremum point (maximum or minimum) is found where f is defined and f' changes signs. In this case:

  • Between 0 and 0.78, the function decreases and at point and it is defined at point 0.78;
  • After 0.78, it increase (has a change of sign) and f is also defined;

Then, x=0.78 is a point of minimum and its y-value is:

f(x) = x^{4}ln(x)

f(0.78) = 0.78^{4}ln(0.78)

f(0.78) = - 0.092

The point of <u>minimum</u> is (0.78, - 0.092)

(c) To determine the inflection point (IP), calculate the second derivative of the function and solve for x:

f"(x) = \frac{d^{2}}{dx^{2}} [x^{3}[4ln(x) + 1]]

f"(x) = 3x^{2}[4ln(x) + 1] + 4x^{2}

f"(x) = x^{2}[12ln(x) + 7]

x^{2}[12ln(x) + 7] = 0

x^{2} = 0\\x = 0

and

12ln(x) + 7 = 0\\ln(x) = \frac{-7}{12} \\x = e^{\frac{-7}{12} }\\x = 0.56

Substituing x in the function:

f(x) = x^{4}ln(x)

f(0.56) = 0.56^{4} ln(0.56)

f(0.56) = - 0.06

The <u>inflection point</u> will be: (0.56, - 0.06)

In a function, the concave is down when f"(x) < 0 and up when f"(x) > 0, adn knowing that the critical points for that derivative are 0 and 0.56:

f"(x) =  x^{2}[12ln(x) + 7]

f"(0.1) = 0.1^{2}[12ln(0.1)+7]

f"(0.1) = - 0.21, i.e. <u>Concave</u> is <u>DOWN.</u>

f"(0.7) = 0.7^{2}[12ln(0.7)+7]

f"(0.7) = + 1.33, i.e. <u>Concave</u> is <u>UP.</u>

4 0
3 years ago
Based on the data set shown, which of the following is a true statement?
patriot [66]
The mean, median, and mode are equal to 1. So among the choices, the first one is correct - mean = mode

Mean - an <em>average </em>of the given set of number; to find this, add the numbers and divide it by 11 (the number of given data)
   = (-1 + -1 + 0 + 1 + 1 + 1 + 1 + 2 + 2 + 2 + 3) / 11
   = 1

Median - the <em>middle or center</em> of the given set; to find this, arrange the numbers in numerical order, then get the center or middle number as the median
   = <span>-1, -1, 0, 1, 1, 1, 1, 2, 2, 2, 3
   = [</span><span>-1, -1, 0, 1, 1,] <u>1</u>, [1, 2, 2, 2, 3]

Mode - is the value that occurs most of the time in the given set; so obviously <em>number 1 occurred four times</em> so 1 is our mode
</span>
3 0
3 years ago
Read 2 more answers
30 points<br> can somebody please help me<br> question below
Inessa05 [86]

Find the total number of dogs by adding each day:

Total dogs = 23

Percent of dogs: Divide the number of dogs by the total number of patients:

= 23 / 50 = 0.46 x 100 = 46%

Use the given formula to find the standard error:

Standard error = √(0.46*(1-0.46)/50) = 0.07

90%: Find Z value for 90% ( 1.645) multiply by SE:

1.645 x 0.07 = 0.115 = 0.12

Now add and subtract that value from the Percent from above:

46 + 12 = 58%

46-12 = 34%

Answer (34%, 58%)

95%: Find Z value for 95% ( 1.96) multiply by SE:

1.96 x 0.07 = 0.137 = 0.14

Now add and subtract that value from the Percent from above:

46 + 14 = 60%

46-14 = 32%

Answer (32%, 60%)

5 0
3 years ago
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