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2k-6-7+3k = 48 need the answer!

Radda [10]

$\huge{\fbox{\sf{ k= 12.2}}}$

Step by step explanation:

Step 1:

$2k-6-7+3k = 48$

Step 2:

$5k - 13 = 48$

Step 3:

$5k = 48 + 13$

Step 4:

$5k = 61$

Step 6:

$k = 12.2✓$

3 0

3 years ago

Read 2 more answers

Ronald Dairo is helping the local indus-

nadya68 [22]

Answer:

Mr. Dairo can produce 20580 pieces of Papaya rosette in two weeks.

Step-by-step explanation:

Papaya rosette pieces on first day = 5890

Papaya rosette Pieces on second day = 7020

Papaya rosette Pieces of third day = 8150

Let

$a_1 = 5890\\a_2 = 7020\\a_3 = 8150$

We can check if these numbers are part of a sequence.

In order to check, common difference will be found first.

$d = a_2-a_1 = 7020-5890 = 1130\\d =a_3-a_2 = 8150-7020 = 1130$

It can be observed that the common difference is same. When the common difference is same, the sequence is said to be an arithmetic sequence.

The formula for arithmetic sequence is given by:

$a_n = a_1+(n-1)d$

Putting the values

$a_n = 5890+(n-1)(1130)\\a_n = 5890+1130n-1130\\a_n =4760+1130n$

The formula for nth term can be used to find any term. As we have to find the number of papaya rosette pieces after two weeks which means that we need to find the number of pieces on 14th day.

So,

$a_{14}= 4760+1130(14)\\a_{14} = 4760+15820\\a_{14} = 20580$

Hence,

Mr. Dairo can produce 20580 pieces of Papaya rosette in two weeks.

5 0

2 years ago

Find the ratio of 15 cm and 9 mm

WITCHER [35]

Answer:

3:5 is the answer of your question

4 0

2 years ago

Read 2 more answers

Find the measure of <1

Dmitry [639]

Consider the triangle (in which angle4 is present)

by angle sum property,

20 + 40 + angle4 = 180

60 + angle4 = 180

angle4 = 180 - 60

angle4 = 120

Also,

angle2 = 120 (vertically opposite angles)

angle1 + angle2 = 180 (linear pair)

angle1 + 120 = 180

angle1 = 180 - 120

angle1 = 60

3 0

2 years ago

It is a well-known fact that 50% of the general population are rascals (P(R) = 0.5) and 50% of the general population are not ra

aleksley [76]

Answer:

The answer is D. 0.75

Step-by-step explanation:

Let call R the event that a person is rascal, RC a person is not rascal, TH a person use top hat and NTH a person don’t use top hat.

From the information on the question we have 4 options with their respective probability:

1. A person could be rascal and use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and use a top hat (0.9), then:

P(R y TH)=0.5*0.9=0.45

2. A person could be rascal and don’t use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and not use a top hat (0.9), then:

P(R y NTH)=0.5*0.1=0.05

3. A person could be not rascal and use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and use a top hat (0.3), then:

P(RC y TH)=0.5*0.3=0.15

4. A person could be not rascal and not use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and not use a top hat (0.7), then:

P(RC y NTH)=0.5*0.7=0.35

Then the probability that a person is a rascal given that he is wearing a top hat could be written and calculate as:

$P(R/TH)=\frac{P(R y TH)}{P(TH)}$

For calculate P(TH) we need to sum all the option in which TH is involve so:

P(TH) = P(R y TH)+ P(RC y TH)

P(TH)=0.45+0.15=0.6

Replacing values on the first equation we get:

$P(R/TH)=\frac{0.45}{0.6} =0.75$

So, the probability that a person is a rascal given that he is wearing a top hat is 0.75

5 0

3 years ago