All categories

3 years ago

What’s the answer?!!!!!!

Mathematics

2 answers:

mars1129 [50]3 years ago

8 0

Answer:

no, because the short sides add up to be more than the 8

arlik [135]3 years ago

7 0

Answer:

Try Yes.....

.................

You might be interested in

What's the unit rate of 2.50 for 5 onces

bulgar [2K]

2.50/5 0.50 an ounce

5 0

3 years ago

Can anyone help me with the answer for number 4

klio [65]

Answer:

Step-by-step explanation:

Given K is the midpoint of JL, then

JK = KL ← substitute values

6x = 3x + 3 ( subtract 3x from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Hence

JK = 6x = 6 × 1 = 6

KL = 3x + 3 = (3 × 1) + 3 = 3 + 3 = 6

JL = 6 + 6 = 12

7 0

3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0

3 years ago

Will give brainliest <br> What is the measure of angle P in the figure shown here?

DaniilM [7]

Answer:

Step-by-step explanation:

66*2=132

180-132=48

6 0

3 years ago

Round 78,879 to the nearest ten

Inessa [10]

The answer is 78,880

4 0

3 years ago

Read 2 more answers