x 
-9; x 
6 or in interval notation [-9,6]
To find out what are the steps in solving the below inequality:
Given equation is 2x - 3 > 15
The absolute value function takes any term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent.
−15≤2x-3≤15
First, subtract 3 from each segment of the system of equations to isolate the x term while keeping the system balanced:
−15−3≤2x-3−3≤15−3
−18≤2x-6≤12
−18≤2x-6≤12
Now, divide each segment of the system by 2 to solve for x while keeping the system balanced:
-9 x 6
or
x -9; x 6
or in interval notation [-9,6]
on the horizontal axis.
The lines will be a solid line because the inequality operators contain "or equal to" clauses.
We will shade between the lines to show the interval:
Hence the steps to solve an inequality has been show
To learn more about inequalities click here brainly.com/question/24372553
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Multiply the first number by 0.032 then add it to the first number and that will be your answer
Answer: Ok for the first two they are true.
Step-by-step explanation: So how you would do this is simple, so for # 2 2x-5=11 (x) represents a number and you have to find it. So For this one put an eight in the x's place and that makes 2(8)-5=11 so when you see 2x that mean 2 times what ever x is. so 2x8=16, 16-5 =11.
Answer:
When we do a reflection of a point (x, y) about a given line, the distance between the point (x, y) and the line is invariant under the transformation.
In the case of reflection over x-axis we have:
T (x, y) => (x, -y)
In the case of reflection over the y-axis, we have:
T (x, y) => (-x, y)
Because these two lines are perpendicular, a reflection over the x-axis leaves the distance between the point and the y-axis invariant (and the same for the inverse case)
Then 4 statements that will always be true:
1) The distance between p' and the x-axis is the same as the distance between p and the x-axis.
2) The distance between p' and the y-axis is the same as the distance between p and the y-axis.
From 1 and 2, we get:
3) The distance between p' and the origin is the same as the distance between p and the origin.
4) As we have a reflection, p' can not be in the same quadrant than p, then p' can not lie on the first quadrant.
