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andreyandreev [35.5K]
3 years ago
6

What is BD? A. 10 B. 12 C. 13 D. 14

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

B 12.

Step-by-step explanation:

BE = ED  (as E is the center of BD - property of a kite).

By Pythagoras:

10^2 = 8^2 + BE^2

BE^2 = 10^2 - 8^2 = 36

BE = 6

So BD = 2*6 = 12.

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An office building casts a 90 foot shadow. At the same time of day, a 5 foot woman standing near the building casts an 8 foot sh
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The answer is 56.25ft
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Graph x≥−1, plz amswer. from khan
Mrrafil [7]

Draw a number line. Plot -1 on the number line and make this a filled in circle. Shade to the right of the filled in circle to indicate the set of values x such that x \ge -1

So x could be -1 or it could be larger. The fact that x = -1 is possible is why we have a closed or filled in circle (instead of an open hole) at this endpoint.

7 0
4 years ago
Find the value for the side marked below.
lions [1.4K]

Answer:

y = 189.8

Step-by-step explanation:

Apply trigonometric function to find y.

Reference angle (θ) = 50°

Adjacent side = 122

Hypotenuse = y

Apply CAH, since the Hypotenuse and the Adjacent are involved.

Thus:

Cos θ = Adj/Hypo

Plug in the values

Cos 50° = 122/y

y*Cos 50° = 122

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y = 189.8 (beater tenth)

6 0
3 years ago
Find the volume of a cylinder with a diameter of 10in and a height of 20in
slavikrds [6]
Volume of cylinder = πr²h

Radius = Diameter ÷ 2
Radius = 10÷ 2
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Volume of the cylinder = 1570.80 in³ (nearest hundredth)

---------------------------------------------------------------
Volume = 1570.80 in³ (Answer C)
---------------------------------------------------------------
5 0
4 years ago
Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, proj,u
11Alexandr11 [23.1K]

Answer:

Take b = \frac{-17}{25}(7,1) as the projection of u onto v and w \frac{1}{25}(-31,217) as the vector such that b+w =u

Step-by-step explanation:

The formula of projection  of a vector u onto a vector v is given by

\frac{u\cdot v}{v\cdot v}v, where cdot is the dot product between vectors.

First, let b ve the projection of u onto v. Then

b = \frac{u\cdot v}{v\cdot v}v= \frac{-6\cdot 7+8\cdot 1}{7\cdot 7+1\cdot 1}(7,1) = \frac{-34}{50}(7,1) = \frac{-17}{25}(7,1)

We want a vector w, that is orthogonal to b and that b+w = u. From this equation we have that w = u-b = (-6,8)-\frac{-17}{25}(7,1)= \frac{1}{25}(-31,217)[/tex]

By construction, we have that w+b=u. We need to check that they are orthogonal. To do so, the dot product between w and b must be zero. Recall that if we have vectors a,b  that are orthogonal then for every non-zero escalar r,k the vector ra and kb are also orthogonal. Then, we can check if w and b are orthogonal by checking if the vectors (7,1) and (-31, 217) are orthogonal.

We have that (7,1)\cdot(-31,217) = 7\cdot -31 + 217 \cdot 1 = -217+217 =0. Then this vectors are orthogonal, and thus, w and b are orthogonal.

5 0
3 years ago
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