7, 13, 19 and 25 have a common difference: 6.
6 added to 7 gives us 13; 6 added to 13 gives us 19, and so on.
Explicit formula: a(n) = 7 + 6(n-1), where 7 is the first term and n is the counter (1, 2, 3, ...).
The first term is 7 (given). This corresponds to n=1.
The second term is a(2) = 7 + 6(2-1), or 7 + 6, or 13. This corresponds to n = 2.
and so on.
Answer:
-49
Step-by-step explanation:
In order to fill in the given expression, we need to know ...
- f(-2) = -4
- f(-3) = 5
- f(-4) = 7
- g(0) = -7
- g(-3) = 3
Then the expression is ...
√(5 -(-4)) -(-7)² +7÷(-7)·(3) = √9 -49 +7/(-7)(3)
= 3 -49 +(-1)(3) = 3 -49 -3
= -46 -3 = -49
Answer:
B
Step-by-step explanation:
Trust me I got it right and you should too
9/5
the distance is 9 over, and 5 up.
Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.