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almond37 [142]
3 years ago
12

Can instantaneous velocity ever be negative?

Physics
2 answers:
kirill115 [55]3 years ago
6 0

Answer:

yes, explained

Explanation:

The instantaneous velocity of an object can be negative. Even though the average velocity of the object in an entire trip is positive, the instantaneous velocity can be negative if the object is moving in negative direction. This direction depends upon the observer. If he considers direction away from him in the right as positive then the direction towards him in the left is negative.

SSSSS [86.1K]3 years ago
4 0
Instantaneous velocity in definition is the average velocity in given particular moment time. Hence, it underlies the context of each velocity at each occupied time and space at that particular moment where you are. Moreover, talking about velocity is vector quantity, which means it both has magnitude and direction. Furthermore, this positive and negative sign attributed to their number means only the specific direction in which the object is going. For example in analogy to average velocity, the initial position of the object at the moment is 2 m/s to the right then the object suddenly changes his position to 3 m/s to the left as his final position. Which is, the exact opposite of the former direction then indicates that the final position is negative, contrary to the initial direction. Just remember that the negative values connoted on the numbers can indicate the opposite direction of either the initial position or an object is downward.



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The bar graph shows energy data taken from a roller coaster at a theme park. analyze the data and assess its validity. 3-5 sente
hichkok12 [17]

This question involves the concepts of the law of conservation of energy, potential energy, and kinetic energy.

The data shown by the bar graph is "valid".

According to the law of conservation of energy, the total energy of the system must remain constant at any given point. Hence, the sum of the kinetic energy and the potential energy of the roller coaster must be constant at any given time.

Considering the bottom of the first hill:

Total Energy at 1st Hill = Kinetic Energy + Potential Energy

From the data given in the bar graph:

Total Energy at 1st Hill = 2,500,000 J + 0 J (since at the bottom potential energy is zero due to zero height)

Total Energy at 1st Hill = 2,500,000 J

Now, considering the top of the second hill:

Total Energy at 2nd Hill = Kinetic Energy + Potential Energy

From the data given in the bar graph:

Total Energy at 2nd Hill = 1,000,000 J + 1,500,000 J

Total Energy at 2nd Hill = 2,500,000 J

Hence,

Total Energy at 1st Hill = Total Energy at 2nd Hill

Therefore, the given bar graph is "valid".

Learn more about the law of conservation of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture explains the law of conservation of energy.

4 0
2 years ago
You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler
scZoUnD [109]

Answer:

q=1.4*10^{-9}C

Explanation:

Given data:

charge on ruler = -14μC

Mass of tissue is 5 g

To Know the minimum charge,  equate electrostatic force to weight  

we have F = W

so\frac{KQq}{r^2} =mg

putting all value in equation,

=\frac{9*10^9*(14*10^{-6})*q}{0.06^2} = 5* 10^{-3}*9.8

solving for q

q =\frac{5* 10^{-3}*9.8 *0.06^2}{9*10^9*(14*10^{-6})}

or q=1.4*10^{-9}C

5 0
3 years ago
A car was at a 30km marker and began to drive. The car passed a 90km marker and the time had changed 30
dolphi86 [110]

Answer:

i think it's 2km pm

Explanation:

2km x 30 60.. start was 30, and now your at 90.. we had to determine how much time it took.. so 2 is the average.. or atleast per minute and sorry it i still didnt answer ur question lol im just trynna help

7 0
2 years ago
Examples of increase in pressure due to increase in applied force<br>​
Nina [5.8K]

Answer:

injecting

Explanation:

5 0
3 years ago
Assume a rectangular strip of a material with an electron density of n=5.8x1020 cm-3. The strip is 8 mm wide and 0.8 mm thick an
vampirchik [111]

Answer: I = 111.69 pA

Explanation: The hall effect is all about the fact that when a semiconductor is placed perpendicularly to a magnetic field, a voltage is generated which could be measured at right angle to the current path. This voltage is known as the hall voltage.

The hall voltage of a semiconductor sensor is given below as

V = I×B/qnd

Where V = hall voltage = 1.5mV =1.5/1000=0.0015V

I = current =?,

n= concentration of charge (electron density) = 5.8×10^20cm^-3 = 5.8×10^20/(100)³ = 5.8×10^14 m^-3

q = magnitude of an electronic charge=1.609×10^-19c

B = strength of magnetic field = 5T

d = thickness of sensor = 0.8mm = 0.0008m

By slotting in the parameters, we have that

0.0015 = I × 5/5.8×10^14 × 1.609×10^-19×0.0008

0.0015 = I×5/7.446×10^-8

I = (0.0015 × 7.446×10^-8)/5

I = 111.69*10^(-12)

I = 111.69 pA

3 0
3 years ago
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