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3 years ago

Can instantaneous velocity ever be negative?

Physics

2 answers:

kirill115 [55]3 years ago

6 0

Answer:

yes, explained

Explanation:

The instantaneous velocity of an object can be negative. Even though the average velocity of the object in an entire trip is positive, the instantaneous velocity can be negative if the object is moving in negative direction. This direction depends upon the observer. If he considers direction away from him in the right as positive then the direction towards him in the left is negative.

SSSSS [86.1K]3 years ago

4 0

Instantaneous velocity in definition is the average velocity in given particular moment time. Hence, it underlies the context of each velocity at each occupied time and space at that particular moment where you are. Moreover, talking about velocity is vector quantity, which means it both has magnitude and direction. Furthermore, this positive and negative sign attributed to their number means only the specific direction in which the object is going. For example in analogy to average velocity, the initial position of the object at the moment is 2 m/s to the right then the object suddenly changes his position to 3 m/s to the left as his final position. Which is, the exact opposite of the former direction then indicates that the final position is negative, contrary to the initial direction. Just remember that the negative values connoted on the numbers can indicate the opposite direction of either the initial position or an object is downward.

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VLD [36.1K]

Answer:

(a) The distance-time graph for an object with uniform speed is giving by a straight line sloped graph with a constant positive or negative gradient as shown in the attached diagram

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Explanation:

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3 years ago

A proton is released in a uniform electric field, and it experiences an electric force of 2.04×10−14 N toward the south.

Lemur [1.5K]

Answer:

Part A:

$E=127500N/C\\E=1.275*10^{5} N/C$

Part B:

Option B (Towards the South)

Explanation:

Part A:

Magnitude if electric field E:

E=Force/charge

Force=2.04×10−14 N

Charge=1.6×10−19 C

$E=\frac{2.04*10^{-14}}{1.6*10^{-19}} \\E=127500N/C\\E=1.275*10^{5} N/C$

Part B:

Option B (Towards the South)

As electron is experiencing the force towards south,it means the direction of the electric field is towards the south because direction of field lines is from positive to negative, so proton is moving towards south it means negative charge is in south to which proton is attracted. So electric field is towards South.

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3 years ago

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3 years ago

Read 2 more answers

A bicyclist travels in a circle of radius 30.0 m at a constant speed of 8.00 m/s. the bicycle-rider mass is 82.0 kg calculate ne

IceJOKER [234]

F=m*(v^2/r)
F=82*(8^2/30)
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