Answer:
Workdone in bringing a unit positive charge from low potential to higher potential against the electric field is electric potential energy.
Electric potential difference is yhe difference of potential energy at the terminals of battery or conductor eire attached to the battery.
Explanation:
Answer:
Population I stars are usually the blue younger stars. They orbit in the disk and they are relatively rich in metals. Population II stars are the red, older stars that lies in the bulge and halo of the Galaxy. They orbits in the elliptical orbits in the halo.
Population I stars include the sun and tend to be luminous, hot and young, concentrated in the disks of spiral galaxies. They are particularly found in the spiral arms. while, Population II stars tend to be found in globular clusters and the nucleus of a galaxy. They tend to be older, less luminous and cooler than Population I stars. They have fewer heavy elements.
The solution for this problem:
PV = nRT
But we are looking for n so, alter the original formula:
n = PV / RT
= (1.00 atm) x (2.09 x 10^8 L) / ((0.08205746 L atm/K mol) x (25.1 + 273.15 K))
= 8539801.26 mol H2
total volume = (8539801.26 mol H2) x (-286 kJ/mol H2) = -2.44 x 10^9 k J
