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julsineya [31]
3 years ago
5

. -3(2x + 1) = 2(-3x - 1)

Mathematics
1 answer:
Marina CMI [18]3 years ago
4 0
No solution to this problem
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Please help and thank you
azamat

Answer:

b

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
3. Which linear equation corresponds to the line graph?
iogann1982 [59]

Answer:

Y=1/3x

Step-by-step explanation:

1) there is no y intercept as x=0 when y=0 so that rules out y=x-2

2) next, we will use the formula for slope to find the value of m

Y2-Y1/X2-X1

Where y2=-1

Y1=0

X2=-3

X1=0

So

-1-0/-3-0=-1/-3

Aka 1/3

So y=1/3x

Hope this helps!

3 0
3 years ago
What is the value of x? inscribed angles
Flura [38]

The value of x is 84°.

Solution:

Measure of intercepted arc = 168°

Measure of angle x = ?

<u>Tangent-chord relationship:</u>

<em>If a tangent and a chord intersect at a point, then the measure of each angle formed is half of the measure of its intercepted arc.</em>

$\Rightarrow \angle x = \frac{1}{2}\times 168^\circ

$\Rightarrow \angle x = 84^\circ

The value of x is 84°.

8 0
3 years ago
1. Which of the following is an arithmetic sequence?
Ronch [10]

i say C. -5, -2, 1, 4, 7 is your answer for question 1.

and for question 2 i think is E. -6, -4, -2, 0, 2.

7 0
3 years ago
Read 2 more answers
Why is the number of operators per shift multiplied by approximately 4.5 to obtain the total number of operators required to run
4vir4ik [10]

I believe you meant "why is the number of shifts multiplied by approximately 4.5 to obtain the total number of operators required to run the plant"

Answer and Explanation:

There are 3 shifts per day, 49 weeks per year and 5 shifts per operator per week

To get total number of operators required to run the plant, we multiply number of shifts in a year by number if operators per shift.

49 weeks×5 shifts= 245 shifts per operator per year

365×3 shifts= 1095 shifts per year

1095/245=4.5 operators per shift

total number of operators required to run the plant(per day) = 4.5×3= 13.5 approximately 14

total number of operators required to run the plant(per year) =4.5×1095=4927.5 approximately 4928

3 0
3 years ago
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