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vazorg [7]
3 years ago
13

what is the pressure of a mixture of co2, so2, and h2o gasses, if each gas has a partial pressure of 25 kpa?

Chemistry
2 answers:
vodka [1.7K]3 years ago
8 0

Answer: 75 kPa

Explanation: According to Dalton's law, the total pressure of a mixture of gases is the sum of individual pressures exerted by the constituent gases.

p_{total}=p_A+p_B+p_C

Thus p_{total}=p_{CO_2}+p_{SO2}+p_{H_2O}

Given:

p_{CO_2}=25kPa

p_{SO_2}=25kPa

p_{H_2O}= 25kPa

Thus p_{total}=25Pa+25kPa+25kPa

p_{total}=75kPa

Thus the pressure of mixture of gases is 75 kPa.

VikaD [51]3 years ago
7 0
Are three mixtures:

CO₂ , SO₂ , H₂O  so :

25 Kpa x 3 =  75 Kpa


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A gas has a volume of 30 L at 105 kPa. What pressure is required to compress the gas to 21 L?
Aloiza [94]

Answer: 150 kPa

Explanation:

Given that,

Original volume of gas V1 = 30L

Original pressure of gas P1 = 105 kPa

New pressure of gas P2 = ?

New volume of gas V2 = 21L

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

105 kPa x 30L = P2 x 21L

3150 kPa L = P2 x 21L

P2 = 3150 kPa L / 21 L

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Which describes what a velocity/time graph would look like with no acceleration?
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A copper rod that has a mass of 200.0 g has an initial temperature of 20.0°C and is heated to 40.0°C. If 1,540 J of heat are nee
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Answer:

Specific heat of copper = 0.385 J/(gi°C)

Explanation:

Given:

Mass of copper (m) = 200 g =

Initial temperature (T1) = 20°C

Final temperature (T2) = 40°C

Heat needed (Q) = 1,540 J

Find:

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⇒ Change in temperature (ΔT) = T2 - T1

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