The ionization equation is:
HF ⇄ H(+) + F(-)
The ionization constant is Ka = [H(+)] * [H(-)] / [HF]
=> [H(+)] * [F(-)] = Ka * [HF]
Given that Ka < 1
[H(+)] * [F(-)] < [HF]
Which is [HF] > [H(+)] * [F(-)] the option a. fo the list of choices.
Volume = (4/3) × π × r^3
R = 1/2 D
R = 7
V = 4/3 x π x 7^3
Exact Form:
1372 π/ 3
Decimal Form:
1436.75504024
Answer:
5 1 2 4and 3 this is correct way
Answer:
Cyanide
Explanation:
<em>Molecular Structure of Each Answer</em>
A: CN-
B: NO3-
C: OH-
D: SO4 2-
As you can see, only A (Cyanide) is the only compound that does not contain oxygen, meaning it is NOT an oxyanion.
Elements in the same group have similar reactivities. For example, elements in group 1 are highly reactive, since they can all take in 7 electrons. Hope I helped!
