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Alla [95]
2 years ago
15

Which of the following compounds does NOT contain molecules? O CO2 ОН2 O Naci OH20

Chemistry
2 answers:
wel2 years ago
7 0

Answer:

Explanation:

NaCl does not contain molecules

sdas [7]2 years ago
6 0

NaCl does not contain molecules. NaCl is an ionic compound which is composed ions( Na+ and Cl-) that are attracted to each other because of their opposite charges. The chemical formula representation of an ionic compound is called a formula unit. Molecular compounds are covalent compounds which are made up of atoms sharing some of their valence electrons for stability.

Further Explanation:

Ionic Compounds

  • Compounds that are made up of a metal and a non-metal are called ionic compounds.
  • The metal transferred one or more valence electrons to the non-metal atom resulting in the formation of charged particles called the metal cation and the non-metal anion.
  • The cation is positively charged and the anion is negatively charged. Because of their opposite charges, the ions tend to attract each other and move closer to each other forming the crystal lattice or the 3-D arrangement of an ionic compound.
  • The simplest ratio of the ions in a crystal lattice is called the formula unit of the ionic compound and is used as the chemical formula of the ionic compound.

Covalent Compounds

  • Covalent compounds are made up of two or more non-metals that are chemically combined.
  • The non-metal atoms in the compound share valence electrons to be stable.
  • Covalent compounds are also called molecules which are groups of 2 or more atoms that are chemically bonded to each other.

Among the choices only NaCl is an ionic compound:

CO2 - carbon, C <em>(non-metal)</em> ; oxygen, O <em>(non-metal)</em> --> COVALENT

H2 - hydrogen, H <em>(non-metal)</em> --> COVALENT

NaCl - sodium, Na <em>(metal)</em> ; chlorine, Cl (<em>non-metal)</em> --> IONIC

H2O - hydrogen, H <em>(non-metal)</em>; oxygen, O <em>(non-metal)</em> --> COVALENT

Learn  More:

  1. Learn more about chemical formula  brainly.com/question/9739060
  2. Learn more about molecular formula brainly.com/question/9297668
  3. Learn more about ions brainly.com/question/269828

Keywords: ionic compound, covalent compounds, molecule

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The orbital hybridization of the central carbon atom in CSe2 is sp.

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4 0
2 years ago
1 point
yawa3891 [41]
No one can read that
5 0
2 years ago
Which element, if combined with chlorine, will have the greatest attraction for the chlorine electrons? N P As
Mumz [18]
Basically, the answer for this would be N or NITROGEN. If we combine nitrogen with chlorine, what happens is that, it can attract more chlorine electrons towards itself. The reason is that, nitrogen is considered more electronegative compared to chlorine. So best answer for this is the first option. 
5 0
2 years ago
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Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse
amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given  by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0
2 years ago
Read 2 more answers
2. What ions are present in what ratio in a solution of aqueous calcium chloride?
Alenkasestr [34]

Answer:

\mathrm{Ca}^{2+} \text { and } \mathrm{Cl} \text { - ions are present in } 1: 2 \text { ratio in a solution of aqueous calcium chloride. }

Explanation:

Here in Calcium Chloride ionic bond is present in between calcium and chlorine atoms. As we know according to Octet rule calcium have two excess atoms and for matching nearest noble gas electronic configuration. It donate two electrons to gain more stability and form \mathrm{Ca}^{2+}, while chlorine is deficient from one electron to meet nearest noble gas electronic configuration therefore two chlorine atoms accept excess electron from calcium individually and form two\mathrm{Cl}^{-} ions.

\text { Equation is as follows: } \mathrm{Ca}^{2+}+2 \mathrm{Cl}^{-} \rightarrow \mathrm{CaCl}_{2}

Hence aqueous solution of calcium chloride breaks the ionic bond pairing in one \mathrm{Ca}^{2+}and two\mathrm{Cl}^{-}ions: \mathrm{CaCl}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O} \quad \mathrm{Ca}^{2+}(\mathrm{ag})+2 \mathrm{Cl}(\mathrm{ag})

5 0
3 years ago
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