Can any negative integer be greater than a positive integer explain

1 answer:

5 0

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

$y < 0 < x$

and since the relation of order "<" is transitive, this implies

$y < x$

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Three rational numbers between 5/31 and 6/31

Ludmilka [50]

Answer:

$\dfrac{26}{155}$ , $\dfrac{27}{155}$ , and $\dfrac{28}{155}$ .

Step-by-step explanation:

What is a rational number? By definition, a rational number can be represented as the fraction of two integers.

The goal is to find three fractions in the form $\dfrac{p}{q}$ between $\dfrac{5}{31}$ and $\dfrac{6}{31}$ .

$\dfrac{5}{31} < \dfrac{p}{q} < \dfrac{6}{31}$ .

At this moment, there doesn't seems to be a number that could fit. The question is asking for three of these numbers. Multiple the numerator and the denominator by a number greater than three (e.g., five) to obtain

$\dfrac{25}{155} < \dfrac{p}{q} < \dfrac{30}{155}$ .