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Rzqust [24]
3 years ago
14

Can any negative integer be greater than a positive integer explain

Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

y < 0 < x

and since the relation of order "<" is transitive, this implies

y < x

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8.5+4(1-2.5k)=24.5 round to the nearest hundredth
frosja888 [35]
Hi there! 

Your question: 

8.5 + 49(1-2.5k)=24.5

My answer: 

8.5 + 4(1-2.5k) = 24.5 >>>>>>> first, you have to distribute

8.5 + 4 - 10k = 24.5 >>>>>>>> now, we are going to combine like terms.

12.5 - 10k = 24.5 >>>>>> now, we are going to subtract 12.5 on both sides 

-10k = 12 >>>>>>>>> finally, divide -10 on both sides

k = -1.2


Hope this helps you!


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