1) subtract 2 from both sides:
y-2 = 9x +2 -2
y-2 = 9x
2) divide both sides by 9:
(y-2)/9 = 9x/9
(y-2)/9=x
so it would be (g-10)/f
I think it would be (x+7)/7
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
y = mx+ b
m=slope
-1/2
Step-by-step explanation:
Answer:4000
Step-by-step explanation:
Let them number be a
655% of a=26200
655/100 x a=26200
655a/100=26200
Cross multiplying we get
655a=26200x100
655a=2620000
Divide both sides by 655
655a/655 = 2620000/655
a=4000