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bixtya [17]
3 years ago
10

Can someone please explain this

Mathematics
1 answer:
S_A_V [24]3 years ago
7 0
Oh. It's rounding. So, for example, depending what you were told to round to, the second problem would be 760-330=430
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Practice 7) fill in the blanks.
DiKsa [7]

(h,k) is the vertex

b/2a is the line of symmetry

a > 0 parabola opens upward, vertex is a minimum

a < 0 parabola opens downward, vertex is a maximum

My first answer was deleted lolol

7 0
3 years ago
Can u help me check if this is correct ty
mart [117]

H (4.84) will be the correct answer

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2 years ago
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tensa zangetsu [6.8K]

Answer:

6.7 to 26

Step-by-step explanation:

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3 years ago
C=48y+0.99n solve for y
Ne4ueva [31]

Answer:

  y = (C -0.99n)/48

Step-by-step explanation:

Undo what is done to y, in the reverse order. We have y multiplied by 48 then added to 0.99n. So, we must add the opposite of 0.99n and multiply that result by the reciprocal of 48.

  C = 48y + 0.99n . . . . . . given

  C - 0.99n = 48y . . . . . . add -0.99n

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4 0
3 years ago
Towns P,Q,R and S are shown. Q is 35 km due East of P S is 15km due West of P R is 15km due South of P Work out the bearing of R
Anni [7]

Answer:

Part A

The bearing of the point 'R' from 'S' is 225°

Part B

The bearing from R to Q is approximately 293.2°

Step-by-step explanation:

The location of the point 'Q' = 35 km due East of P

The location of the point 'S' = 15 km due West of P

The location of the 'R' = 15 km due south of 'P'

Part A

To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that \overline{RP} = \overline{SP}, the right triangle ΔRPS is an isosceles right triangle

∴ ∠PRS = ∠PSR = 45°

The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°

Part B

∠PRQ = arctan(35/15) ≈ 66.8°

Therefore the bearing  from R to Q = 270 + 90 - 66.8 ≈ 293.2°

6 0
3 years ago
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