Answer:
1. Five classes in the frequency distribution
2.The mid point of the third class is 24.5
3.The total number of frequency is 100
4.The relative frequency of the third class is (20/100=0.2)
5. We use n-1 because we are dealing with a sample data
6. The mean is 24.5
7. The value of the standard deviation is 11
Step-by-step explanation:
See attached picture for the solutions
80.
Let be the set of people who like cats and the set of people who like dogs. Under the cardinality theorem you have
n(CUD) = n(C) + n(D) - n(CnD)[/tex], isolating the ∩ , you have n∩ = n(C) + n(D) - ∪∩
SAS
547