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3 years ago

Find the sum of the first 10 terms 40, 37, 34, 31

Mathematics

1 answer:

Bezzdna [24]3 years ago

4 0

<h3>Solution :-</h3>

Firstly finding common difference of the series

As we know that

• Common difference ( d ) = t₂ - t₁

→ Common difference = 37 - 40

→ Common difference = - 3

Now, as we know that

• Sn ( Sum of n terms ) = n/2 [ 2a + ( n - 1 ) d ]

Substituting n = 1. Since the sum of no. of terms is 10 . And substituting a = 40 ,since first term is 40

=> S₁₀ = 10/2 [ 2(40) + ( 10 - 1 ) -3 ]

=> S₁₀ = 5 [ 80 - 27 ]

=> S₁₀ = 5 × 53

=> S₁₀ = 265

Hence , sum of first 10 terms ( S₁₀ ) = 265

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If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
A general circle's equation is (x-h)^2+(y-k)^2= r^2
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Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.

Slope-int y=mx+b
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now we plug things in
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Now we just need to rewrite our equation with all our components.
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