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NemiM [27]
3 years ago
9

Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina com 1mx0,8m. Sabendo que ele recortou 2 triângulos, a

mbos com 20cm de base e 30 cm de altura, 2 trapézios ambos com bases de 10cm e 20cm e altura de 7cm. Determine em cm² quanto foi a área da cartolina que sobrou. * 1 ponto 7595cm² 0,7595m² 7190cm² 0.719m²
Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

7190 cm²

Step-by-step explanation:

Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina de 1 m x 0,8m.

Passo 1

Determine a área de todo o papelão

= Temos dimensões = 1mx0,8m

Área = Comprimento × Largura

= 0,8m²

Nós convertemos para cm²

1 m² = 10.000 cm²

0,8m² = x cm²

Multiplicação cruzada

0,8m² × 10.000 cm² / 1 m²

= 8000 cm²

Passo 2

Sabendo que recortou 2 triângulos, ambos com 20cm de base e 30cm de altura

Encontramos a área de um triângulo

= 1/2 × base × altura

= 1/2 × 20 × 30

= 300cm²

Ele cortou 2 triângulos Portanto, o são dos dois triângulos = 300cm² × 2

= 600cm²

etapa 3

Ele também cortou 2 trapézios ambos com bases de 10cm e 20cm e altura de 7cm.

A área de um trapézio =

1/2 (a + b) h

= 1/2 (10cm + 20cm) × 7cm

= 1/2 × 30 × 7

= 105 cm²

Ele cortou dois trapézios, portanto

A área dos dois trapézios do corte = 105cm² × 2

= 210 cm²

Passo 4

A área total do papelão que foi cortado = 600cm² + 210cm²

= 810 cm²

Etapa 5

Determine em cm² quanto de papelão sobrou.

Isso é calculado como:

Área total do papelão - Área total que foi cortada

= 8000 cm² - 810 cm²

= 7190 cm²

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