Start with

Invert both sides:

Consider the square root of both sides with double sign:

We have

and

Answer:
AH = 1 or 4
CH = 4 or 1
Step-by-step explanation:
An altitude divides a right triangle into similar triangles. That means the sides are in proportion, so ...
AH/BH = BH/CH
AH·CH = BH²
The problem statement tells us AH + CH = AC = 5, so we can write
AH·(5 -AH) = BH²
AH·(5 -AH) = 2² = 4
This gives us the quadratic ...
AH² -5AH +4 = 0 . . . . in standard form
(AH -4)(AH -1) = 0 . . . . factored
This equation has solutions AH = 1 or 4, the values of AH that make the factors be zero. Then CH = 5-AH = 4 or 1.
B is false, since by the inclusion/exclusion principle,

By independence, we have
, which is zero if either of
or
is 0, which isn't guaranteed.
Answer:
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
Step-by-step explanation:
Let us revise the trigonometry functions
- Sin(x) = opposite/hypotenuse
- Cos(x) = adjacent/hypoteouse
- Tan(x) = opposite/adjacent
- Csc(x) = hypotenuse/opposit
- Sec(x) = hypotenues/adjacent
- Cot(x) = adjacent/opposite
In the given figure
The opposite side to angle Ф = 8
The adjacent side to angle Ф = 15
Find the hypotenuse using Pythagoras' theorem




Let us use the rules above to find the trigonometry functions
sinФ = 8/17
cosФ = 15/17
tan Ф = 8/15
csc Ф = 17/8
sec Ф = 17/15
cot Ф = 15/8
√29/2 since cotangent deals the reciprocal of tangent and cotangent value is adjacent side/opposite side