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3 years ago

45 POINTS AND BRAINLIEST IF CORRECT

Mathematics

1 answer:

natita [175]3 years ago

5 0

Answer:

2x+100

Step-by-step explanation:

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the price of an item has been reduced by $2.72 . the new sale price is $96.09 . what was the original price?

stellarik [79]

You add the two numbers together and get $98.81

6 0

3 years ago

8+—3(6+—6a) help please

LenKa [72]

We know that:

$(+)+(-)=(-)$

and:

$(-)*(+)=(-)$

$8+(-3)[6+(-6a)]=8+(-3)*6+(-3)*(-6a)=8-18+18a$ $=(-10)+18a$

if you have solve for $a$ then:

$(-10)+18a=0$
$18a=10$
$a= \frac{10}{18}$
$a=\frac{5}{9}$

5 0

3 years ago

in the following diagrams ABD=y,DBC=x,EFH=y, EFG=x and PQS=SQR=x.write the following in terms of x and y ABC

Leokris [45]

Angles are the space between intersecting lines, and they are measured in degrees or radians

The measure of angle ABC is y + x

<h3>How to determine angle ABC</h3>

The given parameters are:

ABD=y,

DBC=x,

EFH=y,

EFG=x

PQS = SQR = x

To determine the measure of angle ABC, we make use of angle ABD and angle DBC

Note that angle ABD and angle DBC have common vertices at points B and D

So, we have:

ABC = ABD + DBC

Substitute known values

ABC = y + x

Hence, the measure of angle ABC is y + x

Read more about angle measures at:

brainly.com/question/17972372

3 0

3 years ago

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$

$h(4\,s) = 576\,ft$

The highest altitude that the object reaches is 576 feet.

6 0

4 years ago

Can somebody help me out ??

julia-pushkina [17]

Answer: y = -3/2x -5

explanation:
y = mx + b
7 = -3/2(-8)+b
7= 12 +b
subtract 12 on both sides
-5 = b

y = -3/2x - 5

3 0

3 years ago