V = 1/3Bh
B = 1/2(b1 + b2)t
V = 1/3[1/2(b1 + b2)t] * h
h = 24
b1 = 13
b2 = 29
t = ?
V = 2856
Substitute:
2856 = 1/3[1/2(13 + 29)t](24)
2856 = 1/6(42)(24)t
2856 = 7(24)t
2856 = 168t
t = 2856/168 = 17 in height of the trapeziod
25-5.25 gives you the amount of money Craig can spend for games. 25-5.25=19.75. If Craig can spend 19.75, he can play only 4 whole games.