A trapeziodal pyramid has a volume 2856insquared the height of the pyramid is 24in and the lengths of the 2 two bases of the tra
1 answer:
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Hello there! you can use the expression !
To find slope, subtract the y values over the x values.
In this case:
2 - - 1 / - 3 - 7
3 / -10
So, -3/10 would be the slope of these points.
Hope this helps, have a great day!
CHECK THE ATTACHMENT FOR THE FIGURE OF THE QUESTIONS
Answer:
Option A. is correct x = 4
Step-by-step explanation:
From the given figure
The adjacent of the given right angle triangle is
8 units which is the base,
Then x units is the opposite of the right angle triangle which is the height.
The hypotenuse side also has x units
Then value of x is required,
But going by right angle triangle trigonometry
cos(x) = adjacent / hypotenuse
Where adjacent= 8 unit
cos( 60) = 8/x
1/2 = 8/x
x = 8/2
= 4unit
Hence, Option A is correct, with 4 units
<h2>a. What is your equation?</h2>
This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:
Where:
So:
Finally, the equation is:
The rocket will reach the maximum height at the vertex of the parabola described by the equation . Therefore, our goal is to find
at this point. In math, a parabola is described by the quadratic function:
So the x-coordinate of the vertex can be calculated as:
From our equation:
So:
So the rocket will take its maximum value after 1.99 seconds.
<h2>c. What is the maximum height the rocket will reach?</h2>
From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by . Thus, we can find this as follows:
So the maximum height the rocket will reach is 66.68ft
<h2>d. How long is the rocket in the air?</h2>
The rocket is in the air until it hits the ground. This can be found setting , so:
We can't have negative value of time, so the only correct option is and rounding to the nearest hundredth we have definitively: