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Katen [24]
3 years ago
11

ms.white is making book marks for her first grade class each bookmark has a gold tassel.8 book marks are in one package and she

will need for 30 students then how many packages will she need
Mathematics
2 answers:
ioda3 years ago
7 0
Maybe its about 3 so yea
s2008m [1.1K]3 years ago
4 0
She’s going to need 4 packages of bookmarks because 30 divided by 8 is 3.75 (which is rounded to 4)
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The answer is 0 solutions. This problem has none
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At Dwayne's Swimwear, 75% of the 92 swimsuit styles are bikinis. How many bikini styles are there?
bogdanovich [222]

Answer:

69 styles

Step-by-step explanation:

75%= 3/4

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3 years ago
The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10
Rama09 [41]

Answer:

a) E(X) = 6.45

b) E(X^{2} )= 57.25

c) V(X) = 15.648

d) E(3X + 2) = 21.35

e) E(3X^{2} +2) = 173.75

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) E(X) = \sum xP(x)

E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45

b)

E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\  E(X^{2} )= 57.25

c)

V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648

d)

E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35

e)

E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75

f)

V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832

g)

E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45

h)

V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648

6 0
3 years ago
Write 7.5% as a fraction in lowest terms
denis-greek [22]
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Answer:

A

Step-by-step explanation:

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