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The heights of a group of sixth graders' are summarized below. If another sixth grader were to be measured, what would be a good

olga nikolaevna [1]

Using the mean, median and mode we can assume that a good prediction for her height would be 55 inches.

In the given data ,

Range of the data is 10. So all the values are between 50 and 60.

mode of the data is 57 , and the mean is 55 and the median is 55

Therefore a random 6th grader can have any value between 50 and 60 since it is the range.

Now the mean and median of the function will be closest to a random value.

Hence of all the options 55 is the most efficient explanation of the central tendency of the dataset .

When the probability density function contains a large number of local maxima, the edge points of a continuous distribution are frequently referred to as the distribution's modes.

Any x value that causes the density function probability of a variate to reach a locally maximum value is often thought of as a mode, making any peak a mode.

The median is the value that divides the top and bottom halves of a large dataset, a demographic, or a probability distribution in statistics and probability theory.

Hence of all the options 55 is the most efficient explanation of the central tendency of the dataset .

To learn more about mode visit:

brainly.com/question/300591

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3 0

1 year ago

Please help i’ll give brainlist

yan [13]

Answer:

from top to bottom = c, d, a, b

Step-by-step explanation:

8 0

3 years ago

Evaluate the given expression if x = 25, y = 10, w = 11, and z = 18. (see the image)

hammer [34]

Answer:

D

Step-by-step explanation:

So we have the expression:

$(x-y)^2+10wz$

And we want to evaluate it when x=25, y=10, w=11, and z=18.

So, substitute these values for the variables:

$=(25-10)^2+10(11)(18)$

First, subtract within the parentheses:

$=(15)^2+10(11)(18)$

Square 15:

$=225+10(11)(18)$

Now, multiply the terms on the right. 10 times 11 is 110:

$=225+110(18)$

Multiply:

$=225+1980$

Finally, add:

$=2205$

So, our answer is D.

And we're done!

8 0

3 years ago

Read 2 more answers

Write 8 * 10^-7 in standard form 8*10^-7 =____

tino4ka555 [31]

Answer:

0.0000008

Step-by-step explanation:

Given

8*10^-7

Converted to standard form

8*10^-7 = 8*0.0000001 = 0.0000008

4 0

3 years ago

Read 2 more answers

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

so

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago