Answer:
x = 7
y = 12
Step-by-step explanation:
To do this question you have to know your exponent rules, but also you need to know how to add fractions.
To multiply
6^(1/3) × 6^(1/4)
you can keep the 6 and just add the exponents.
That's why the answer is set up on the form 6^(x/y)
To add fractions, you need a common denominator, it is 12.
1/3 is 4/12.
1/4 is 3/12.
So 1/3 + 1/4
is the same as:
4/12 + 3/12
= 7/12
7/12 is the exponent you are looking for.
x = 7 and y = 12.
6^(1/3) × 6^(1/4)
=6^(7/12)
Answer:
0.3339 = 33.39% probability that both Dave and Mike will show up
Step-by-step explanation:
Probability of independent events:
If A and B are independent events, the probability of both happening at the same time is given by:

In this question:
Event A: Dave shows up.
Event B: Mike shows up.
Christine knows that there is a 47% chance that Dave will not show up and a 37% chance that Mike will not show up.
This means that
.
a. What is the probability that both Dave and Mike will show up

0.3339 = 33.39% probability that both Dave and Mike will show up
Answer: yes
Step-by-step explanation:
I believe that y is equal to -5.
y=-5
- Square <em>:</em><em>4</em><em> </em><em>sides</em><em>,</em><em>each</em><em> </em><em>side</em><em> </em><em>9</em><em>0</em><em> </em><em>degrees</em><em> </em><em>.</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>:each angle is 90 degrees
: 4 diagonals
- Rectangle: 4 sides..4 angles..2 diagonals..
- Rhombus : <u>4</u><u> </u><u>sides</u><u>.</u><u>.</u><u>2</u><u> </u><u>angles</u><u>.</u><u>.</u><u>.</u><u>2</u><u> </u><u>diagonals</u><u>.</u><u>.</u>
- Parallelogram : 4 sides..4 angles..2 diagonals..
- Quadrilateral: 4 sides...4 angles...4 diagonals..
<em>If</em><em> </em><em>this</em><em> answer</em><em> helps</em><em><u> you</u></em><em><u> plz</u></em><em><u> mark</u></em><em><u> as</u></em><em><u> brainlist</u></em><em><u>.</u></em><em><u>.</u></em>