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3 years ago

Write (2i(1+i)+5)/(1+3i) as a complete number in standard form.

Mathematics

1 answer:

olasank [31]3 years ago

6 0

Answer: basicily its 0

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uysha [10]

The answer is E
step by step explanation:

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2 years ago

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If 4x = 28 then x = 7

Contact [7]

Answer:

correct

Step-by-step explanation:

4 times 7 is 28

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-13d-8=-8-6d equation

olga nikolaevna [1]

Well, for -6d to equal -13d, d would have to be 0 to satisfy this equation

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3 years ago

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Write as a sum, difference or<br> multiple of logarithms.<br> In(8x) = [ ? ]8+ [ ]x

deff fn [24]

Answer:

In(8x)=[In]8 + [In]x

Step-by-step explanation:

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$In(8x)=[In]8 + [In]x$

8 0

2 years ago

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago