You're given that φ is an angle that terminates in the third quadrant (III). This means that both cos(φ) and sin(φ), and thus sec(φ) and csc(φ), are negative.
Recall the Pythagorean identity,
cos²(φ) + sin²(φ) = 1
Multiply the equation uniformly by 1/cos²(φ),
cos²(φ)/cos²(φ) + sin²(φ)/cos²(φ) = 1/cos²(φ)
1 + tan²(φ) = sec²(φ)
Solve for sec(φ) :
sec(φ) = - √(1 + tan²(φ))
Given that cot(φ) = 1/4, we have tan(φ) = 1/cot(φ) = 1/(1/4) = 4. Then
sec(φ) = - √(1 + 4²) = -√17
Answer:
y = -20x + 100
Step-by-step explanation:
As per your requirement For Part B, the solution is
The equation in slope-intercept form to model the relations is below:-
To reach 2 points on the graph the line passes through
lets use p1(0, 100), p2(1, 80)
now we will compute the slope:
= -20
and now use line equation in form point-slope:
y - y1 = m(x - x1)
y - 100 = -20(x - 0)
y = -20x + 100
Answer:
D) collinearity
Step-by-step explanation:
Collinearity occurs when a few of the independent variables are related or match up. Collinearity increases the large proportion the variance of an estimated regression coefficient which leads to certain regression coefficient having wrong signs. It is used to explain the relationship between two variables.
Answer:
<u><em>C. strong negative</em></u>
Step-by-step explanation:
The reason why is because, the student's grade is falling dramatically while they watch TV. So therefore, we can erase A and D. B maybe however, it isn't "weak" but it is a heavy decrease. Therefore, your answer would be C.
