X = approximately 633
Steps:
lnx + ln3x = 14
ln3x^2 = 14 : Use the log property of addition which is to multiply same log together so you multiply x and 3x because they have log in common
(ln3x^2) = (14) : take base of e on both sides to get rid of the log
e e
3x^2 = e^14 : e cancels out log on the left side and the right side is e^14
x^2 = e^14 / 3 : divide both sides by 3
√x^2 = <span>√(e^14 / 3) : take square root on both sides to get rid of the square 2 on x
</span>
x = √(e^14) / <span>√3 : square root cancels out square 2 leaving x by itself
x = e^7 / </span>√3 : simplify the √(e^14) so 14 (e^14) divide by 2 (square root) = 7<span>
x = </span>633.141449221 : solve
We know that
[area of the painting]=13 in* 17 in-----> 221 in²
if a<span>n artist painting at
$0.30 per --------------> 1 in</span>²
x$--------------> 221 in²
X=221*0.30------> x=$66.30
the answer is
$66.30
Answer:
G. 12
Step-by-step explanation:
Rachel = x
Trina = y
x = 2y - 6
x = (2x9) - 6
x = 18 - 6
x = 12
<h3>
Answer: x = 9</h3>
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Explanation:
The smaller angles HGE and EGF combine to form the largest angle HGF.
This is an example of the angle addition postulate.
(angle HGE) + (angle EGF) = angle HGF
(3x+11) + (110) = 16x+4
3x+121 = 16x+4
121-4 = 16x-3x
117 = 13x
13x = 117
x = 117/13
x = 9 which is the final answer
We can stop here.
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Extra info (optional section)
Use this x value to find each angle shown below
- angle HGE = 3x+11 = 3*9+11 = 27+11 = 38 degrees
- angle HGF = 16x+4 = 16*9+4 = 144+4 = 148 degrees
Then notice how,
(angle HGE)+(angle EGF) = 38+110 = 148
which is exactly the measure of angle HGF
This confirms that the equation
(angle HGE) + (angle EGF) = angle HGF
is true for that x value of x = 9. Therefore, the answer is confirmed.
