The general solution of a differential equation of the form ay'' + by' + cy is given by Ae^mx + Be^nx; where m and n are the root of the quadratic equation ax^2 + bx + c The general solution of <span>y'' + 4y' is given by </span><span>Ae^mx + Be^nx; where m and n are the root of the quadratic equation x^2 + 4x = 0 x(x + 4) = 0 x = 0 or x = -4
Therefore, the general solution is Ae^(-4x) + Be^0x = Ae^(</span>-4x) + B
