Answer:
9x² - 4/3x + ¼
Step-by-step explanation:
(3x - ½)²
(3x - ½)(3x -½)
9x² - ⅔x - ⅔x + ¼
9x² - 4/3x + ¼
To add and get the sum
346
421
+152
We start on the ones place 6 + 1 + 2 = 9, the sum of the digits in the ones place is not up to 10, we will not regroup this ones place.
So, basically the answer to 13a is NO.
Since we are not able to regroup the ones place there is no regrouped tens to add, therefore the answer to 13b is also NO.
Next is the tens place, 4 +2 +5 = 11, the sum of the digits in the ones place is up to 10 so we regroup the tens place.
Thus, the answer to 13c is YES.
Since, we regrouped the ones place, we add the regrouped hundred, thus the answer to 13d is YES.
Finally, for the hundred place, 1 + 3 + 4 + 1 = 9
Therefore, the sum of
346
421
+ 152
is 919
Answer:
x > 15
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define inequality</u>
5x - 7 > 4x + 8
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract 4x on both sides: x - 7 > 8
- Add 7 on both sides: x > 15
Here we see that any value <em>x</em> that is greater than 15 would work as a solution to this inequality.
Plug the value of x in the equation
2(6 - y) = 8
12 - 2y = 8
-2y = -4
y = 2
