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Oksi-84 [34.3K]
3 years ago
5

What two numbers if multiplied equal 144.585?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0
48.195*3
idk if u wanted any numbers that work but ya hope that helped :)
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The sum of the fractions 2/y-3 and 6/y+3 is equal to their
Sphinxa [80]

Step-by-step explanation:

Move expression to the left side and change its sign

5

y

−

3

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10

y

2

−

y

−

6

−

y

y

+

2

=

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Write

−

y

as a sum or difference

5

y

−

3

+

10

y

2

+

2

y

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−

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and

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3

from the expression

5

y

−

3

+

10

y

(

y

+

2

)

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3

(

y

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2

)

−

y

y

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2

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Factor out

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from the expression

5

y

−

3

+

10

(

y

+

2

)

(

y

−

3

)

−

y

y

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2

=

0

Write all numerators above the least common denominator

5

(

y

+

2

)

+

10

−

y

(

y

−

3

)

(

y

+

2

)

(

y

−

3

)

=

0

Distribute

5

and

−

y

through the parenthesis

5

y

+

10

+

10

−

y

2

+

3

y

(

y

+

2

)

(

y

−

3

)

=

0

Collect the like terms

8

y

+

20

−

y

2

(

y

+

2

)

(

y

−

3

)

=

0

Use the commutative property to reorder the terms

−

y

2

+

8

y

+

20

(

y

+

2

)

(

y

−

3

)

=

0

Write

8

y

as a sum or difference

−

y

2

+

10

y

−

2

y

+

20

(

y

+

2

)

(

y

−

3

)

=

0

Factor out

−

y

and

−

2

from the expression

−

y

(

y

−

10

)

−

2

(

y

−

10

)

(

y

+

2

)

(

y

−

3

)

=

0

Factor out

−

(

y

−

10

)

from the expression

−

(

y

−

10

)

(

y

+

2

)

(

y

+

2

)

(

y

−

3

)

=

0

Reduce the fraction with

y

+

2

−

y

−

10

y

−

3

=

0

Determine the sign of the fraction

−

y

−

10

y

−

3

=

0

Simplify

10

−

y

y

−

3

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When the quotient of expressions equals

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, the numerator has to be

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10

−

y

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Move the constant,

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y

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−

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Change the signs on both sides of the equation

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6 0
3 years ago
Read 2 more answers
The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
4 years ago
The ratio of the volume of two solids is 1331:729. What is the ratio of the surface area
katovenus [111]
Volume ratio = 1331/729 which is the cube of the linear scale factor.
To find the linear scale factor, let find the cubic root of the numerator & the denominator:

∛1331 = ∛11³  = 11

&  ∛729 = ∛9³  = 9

So the linear scale is 11/9 ==> then the ratio of their surface area will be:

11²/9² ==> 121/81.
Note, if you have a linear scale, then the surface will be the square othis scale & the volume will be the cube of the linear scale
8 0
3 years ago
Solve and graph the inequality 6 + 3n ≤40
Kazeer [188]
6+3n≤40
Use inverse operations i.e.
4x+2<10
    -2    -2
4x<8
4*x/4<8/4
x<2
7 0
3 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
3 years ago
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