The answer to your question is,
Each time they assume the sum is rational; however, upon rearranging the terms of their equation, they get a contradiction (that an irrational number is equal to a rational number). Since the assumption that the sum of a rational and irrational number is rational leads to a contradiction, the sum must be irrational.
-Mabel <3
If you would like to know how many kilograms of fruit do you have, you can calculate this using the following steps:
3 4/5 kg of cherries + 2 1/4 kg of strawberries = 3 4/5 + 2 1/4 = 19/5 + 9/4 = 76/20 + 45/20 = (76 + 45) / 20 = 121/20 = 6 1/20 kg of fruit
The correct result would be 6 1/20 kilograms of fruit.
36m+25. ehhwienebtbtbrbve
PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;
PART B
</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;
Answer:
f‐¹(x) = 4x² - 3, for x < 0.
Nice doodle :P
