<span> Given polynomial x^2+8x-48 = 0</span>
<span>x^2+12x-4x-48 = 0</span>
<span>x(x+12)-4(x+12) = 0</span>
<span>(x+12)(x-4) = 0</span>
<span>x+12 = 0</span>
Subtract 12 from each side.
<span>x+12-12 = 0-12</span>
<span>x = -12</span>
<span>and x-4 = 0</span>
Add 4 to each side.
<span>x-4+4 = 0+4</span>
<span>x = 4</span>
<span>Roots are -12,4.</span>
Answer:
the answer is 80 i think
Step-by-step explanation:
bc dependng on 2lw+2lh+2hw, formula 8 and 10 would be length and width
Lets say
8=width
10=lenght
3in=height
u would do
2 x l x w + 2 x l h + 2 x h x w=
2 x 10 x 8 + 2 x 10 x 3 + 3 x 8=
160 + 60 + 48+=
268 is the sa
pls brainliest and more points :0
Answer:
not sure if you're looking for an example of this or not but if you are then it could be something like 12 + 8 because 2/3 of 12 is 8.
Answer:
StartRoot 80 EndRoot
Step-by-step explanation:
|GH|² = (8 - 0)² + (1 - (-3))²
|GH|² = 64 + 16
|GH|² = 80
GH = sqrt(80)
