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Andreas93 [3]
2 years ago
12

Sammy rides his bike to school and to pick up his sister at her school. He rides 4 miles round trip to his school. To his sister

's school is 1 mile round trip. He does this 5 times each week. How many miles does he ride in 12 weeks? A 240 miles B 600 miles C 300 miles D 440 miles5​
Mathematics
1 answer:
KatRina [158]2 years ago
4 0

Answer: 300

Step-by-step explanation: First of all calcute how much per day, which is 5 miles. Then by 5 days which is 25. Now by 12 which is 300.

Hope this helped :)

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(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
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