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denis-greek [22]

3 years ago

8

Ben's living room is a rectangle measuring 11 yards by 204 inches. By how many feet does feet does the length of the room exceed

the width

1 answer:

grigory [225]3 years ago

6 0

Answer:

hope it's helpfull purple you

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Find the value of x and y.

wariber [46]

Answer:

X=63 y=27

Step-by-step explanation:

X and 117 are on a straight line. All straight lines = 180 degrees.

180 - 117 = 63

90 - 63 = 27

6 0

3 years ago

Enter the degree of the polynomial below:<br><br><br> 6x^6 + 9x^3 + 3x^2 - 4x^10 - 9x^5 - 5x^6

Blababa [14]

Answer:

10

Step-by-step explanation:

The highest exponent determines the degree of a polynomial.

3 0

3 years ago

The volume of a rectangular prism (shown below) is 48x^3+56x^2+16x Answer the following questions:

pickupchik [31]

Answer:

(a)

$Length = 8x\\Width = 3x + 2\\Height = 2x + 1$

(b)

$P(2) = 640$

(c)

$Length= 16$

$Width = 8$

$Height =5$

(d)

$Volume = 640$

Step-by-step explanation:

Given

$P(x) = 48x^3 + 56x^2 + 16x$

Solving (a): The prism dimension

We have:

$P(x) = 48x^3 + 56x^2 + 16x$

Factor out 8x

$P(x) = 8x(6x^2 + 7x + 2)$

Expand 7x

$P(x) = 8x(6x^2 + 4x + 3x + 2)$

Factorize

$P(x) = 8x(2x(3x + 2) +1( 3x + 2))$

Factor out 3x + 2

$P(x) = 8x(3x + 2)(2x + 1)$

So, the dimensions are:

$Length = 8x\\Width = 3x + 2\\Height = 2x + 1$

Solving (b): The volume when $x = 2$

We have:

$P(x) = 48x^3 + 56x^2 + 16x$

$P(2) = 48 * 2^3 + 56 * 2^2 + 16 * 2$

$P(2) = 640$

Solving (c): The dimensions when $x = 2$

We have:

$Length = 8x\\Width = 3x + 2\\Height = 2x + 1$

Substitute 2 for x

$Length=8*2$

$Length= 16$

$Width = 3*2+2$

$Width = 8$

$Height = 2*2 + 1$

$Height =5$

So, we have:

$Length= 16$

$Width = 8$

$Height =5$

Solving (d), the volume in (c)

We have:

$Volume = Length * Width * Height$

$Volume = 16 * 8 * 5$

$Volume = 640$

8 0

3 years ago

I can type 40 wpm in one minute how many in 20 minutes

kykrilka [37]

You can type 800 words in 20 minutes

40 x 20 = 800

5 0

3 years ago

Read 2 more answers

A 10 ft. ladder leans against a wall so the base of the ladder is 4 ft. from the wall. how high up on the wall will the ladder r

Andrews [41]

Using Pythagoras theorem:-

10^2 = 4^2 + h^2

h^2 = 100 - 16 = 84

h = sqrt 84 = 9.17 ft answer

3 0

4 years ago