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postnew [5]
3 years ago
5

the area of a rectangular dog pen is 8 1/2 square feet. if the width is 3 2/5 feet, what is the length, in feet?

Mathematics
2 answers:
frez [133]3 years ago
6 0
2.5 ft.

a rectangle's area is Length • Width

8.5 = 3.4 \times x
8.5 \div 3.4 = x
2.5 = x
Setler [38]3 years ago
6 0

Answer:

Area of rectangle is equal to multiply the length by width

i.e A = l\times w           .....[1]

where

A is the area of rectangle ,

l is the length and

w is the width of the rectangle respectively.

Given : Area of rectangular do pen(A) = 8\frac{1}{2} = \frac{17}{2} square feet and width(w) = 3\frac{2}{5} = \frac{17}{5} feet.

To calculate the length in feet.

Substitute the given values in [1],  we get

\frac{17}{2}= l\times \frac{17}{5}

Multiply both sides by \frac{5}{17} we get;

l = \frac{17}{2} \times \frac{5}{17} =\frac{5}{2} = 2\frac{1}{2} feet.

Therefore, the length in feet is, 2\frac{1}{2}

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Step-by-step explanation:

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Kay [80]

Answer:

1) (x + 3)(3x + 2)

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Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

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factor out x+3

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rearrange the equation

5x^2 + 2x - 1 = 0

divide both sides by 5 to cancel out the 5 of first term

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rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

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taking square root on both sides

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shifting 1/5 on the other side

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